c3+c+1...

Cheranus @Cheranus

July 2022 1 6 Report

Сократите Дробь:
1-2с/c3-1 - c-1/c3+c+1

Answers & Comments

nafanya2014

Verified answer

$\frac{1-2c}{c^3-1} - \frac{c-1}{c^2+c+1}= \frac{1-2c}{(c-1)(c^2+c+1)} - \frac{c-1}{c^2+c+1}= \frac{1-2c-(c-1)^2}{(c-1)(c^2+c+1)} = \\ \\ =\frac{1-2c-(c^2-2c+1)}{(c-1)(c^2+c+1)} =\frac{1-2c-c^2+2c-1)}{(c-1)(c^2+c+1)}=\frac{-c^2}{(c-1)(c^2+c+1)}$

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