а) (y-2)(y+6) = y(y+1)
y² + 6y - 2y - 12 = y² + y
3y - 12 = 0
3y = 12
y = 4.
Ответ: 4
б) 20x - x² = 0
20x - x² = 0
x(20 - x) = 0
[x = 0
[x = 20
Ответ: 0, 20
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Answers & Comments
а) (y-2)(y+6) = y(y+1)
y² + 6y - 2y - 12 = y² + y
3y - 12 = 0
3y = 12
y = 4.
Ответ: 4
б) 20x - x² = 0
20x - x² = 0
x(20 - x) = 0
[x = 0
[x = 20
Ответ: 0, 20