[tex]\frac{y-x}{x(x-a)}-\frac{y+a}{a(a-x)} =\frac{y-x}{x(x-a)}+\frac{y+a}{a(x-a)}=\frac{(y-x)a+(y+a)x}{ax(x-a)}=\frac{ay-ax+xy+ax}{ax(x-a)} =\frac{ay+xy}{a(x-a)} =\frac{y(a+x)}{ax(x-a)}[/tex]
Ответ:
x(x−a)
y−x
−
a(a−x)
y+a
=
+
a(x−a)
ax(x−a)
(y−x)a+(y+a)x
ay−ax+xy+ax
ay+xy
y(a+x)
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Answers & Comments
[tex]\frac{y-x}{x(x-a)}-\frac{y+a}{a(a-x)} =\frac{y-x}{x(x-a)}+\frac{y+a}{a(x-a)}=\frac{(y-x)a+(y+a)x}{ax(x-a)}=\frac{ay-ax+xy+ax}{ax(x-a)} =\frac{ay+xy}{a(x-a)} =\frac{y(a+x)}{ax(x-a)}[/tex]
Ответ:
x(x−a)
y−x
−
a(a−x)
y+a
=
x(x−a)
y−x
+
a(x−a)
y+a
=
ax(x−a)
(y−x)a+(y+a)x
=
ax(x−a)
ay−ax+xy+ax
=
a(x−a)
ay+xy
=
ax(x−a)
y(a+x)