Verified answer

[tex]\displaystyle 1)\frac{y^2+3y}{y^2}=\frac{y(y+3)}{y^2}=\frac{y+3}{y}\\ \\2) \frac{x^2-5x}{x^2-25}=\frac{x(x-5)}{(x-5)(x+5)}=\frac{x}{x+5}[/tex]

Ответ:

у+3/у первое

х/х+5 второе