Ответ:

[tex]\frac{x}{x-5}[/tex]

Объяснение:

[tex]\frac{2x}{x-5}+\frac{x}{x+5}+\frac{2x^2}{25-x^2}=\frac{2x}{x-5}+\frac{x}{x+5}-\frac{2x^2}{x^2-25}=\\\\\frac{2x}{x-5}+\frac{x}{x+5}-\frac{2x^2}{(x-5)(x+5)}=\frac{2x(x+5)}{(x-5)(x+5)}+\frac{x(x-5)}{(x-5)(x+5)}-\frac{2x^2}{(x-5)(x+5)}=\\\\\frac{2x(x+5)+x(x-5)-2x^2}{(x-5)(x+5)}=\frac{2x^2+10x+x^2-5x-2x^2}{(x-5)(x+5)}=\\\\\ \frac{x^2+5x}{(x-5)(x+5)}=\frac{x(x+5)}{(x-5)(x+5)}=\frac{x}{x-5}[/tex]