[tex]\dfrac{0{,}3 \cdot 5^2 - 15}{3{,}5+2^2}=\dfrac{0{,}3 \cdot 25-15}{3{,}5+4}=\dfrac{7{,}5-15}{7{,}5}=\dfrac{-7{,}5}{7{,}5}=-\dfrac{7{,}5}{7{,}5}=-1.[/tex]
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[tex]\dfrac{0{,}3 \cdot 5^2 - 15}{3{,}5+2^2}=\dfrac{0{,}3 \cdot 25-15}{3{,}5+4}=\dfrac{7{,}5-15}{7{,}5}=\dfrac{-7{,}5}{7{,}5}=-\dfrac{7{,}5}{7{,}5}=-1.[/tex]