Ответ:

Смотри решение на фото...

Объяснение:

[tex](\frac{5}{x-y})^2:\frac{5x-10y}{x^2-2xy+x^2} =\frac{5^2}{(x-y)^2}:\frac{5(x-2y)}{x^2-2xy+x^2+y^2-y^2} =\\\\=\frac{25}{(x-y)^2}:\frac{5(x-2y)}{x^2-2xy+y^2+x^2-y^2} =\frac{25}{(x-y)^2}:\frac{5(x-2y)}{(x-y)^2+(x^2-y^2)}=\\\\=\frac{25}{(x-y)^2}*\frac{(x-y)^2+(x^2-y^2)}{5(x-2y)}= \frac{5}{(x-y)^2}*\frac{(x-y)^2+(x-y)(x+y)}{(x-2y)}=\\\\=\frac{5}{(x-y)^2}*\frac{(x-y)(x-y+x+y)}{(x-2y)}=\frac{5x^2(x-y)}{(x-y)^2(x-2y)} = \frac{5x^2}{(x-y)(x-2y)}= \frac{5x^2}{x^2-3xy+2y^2}= \frac{5}{2x(x-2y)(x-y)^3}[/tex]