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kalahanm546
@kalahanm546
June 2023
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визначте відношення маси елемента у сполуці Ca(HCO3)2
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timamoro542
Verified answer
Mr(Ca(HCO3)2) = 40+2*1+2*12+6*16= 162
W(Ca) = 40/162 = 0.25 = 25%
W(H) = 2/162 = 0.01 = 1%
W(C) = 24/162 = 0.15 = 15%
W(O) = 96/162=0,59 = 59%
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Answers & Comments
Verified answer
Mr(Ca(HCO3)2) = 40+2*1+2*12+6*16= 162W(Ca) = 40/162 = 0.25 = 25%
W(H) = 2/162 = 0.01 = 1%
W(C) = 24/162 = 0.15 = 15%
W(O) = 96/162=0,59 = 59%