Ответ:
[tex]\displaystyle 1\frac{2}{7}+\left(4,25-3\frac{1}{20}+15,96:4\frac{1}{5}\right):7=2[/tex]
Пошаговое объяснение:
Найти значение выражения:
[tex]\displaystyle 1\frac{2}{7}+\left(4,25-3\frac{1}{20}+15,96:4\frac{1}{5}\right):7[/tex]
Расставим действия:
[tex]\displaystyle 1\frac{2}{7}\stackrel{(5)}+\left(4,25\stackrel{(2)}-3\frac{1}{20}\stackrel{(3)}+15,96\stackrel{(1)}:4\frac{1}{5}\right)\stackrel{(4)}:7[/tex]
[tex]\displaystyle 1)\;15,96:4\frac{1}{5}=15,96:4,2=159,6:42=3,8[/tex]
[tex]\arraycolsep=0.05em\begin{array}{c c c c r r @{\;}l | l}& 1 & 5 & 9, & 6 & & & \;42 \\\cline{1-1}\cline{8-8}~ & 1 & 2 & 6 & & & & \; 3,8\\\cline{2-5} & &3 & 3 & 6 & \\\cline{2-2} & & 3 & 3 & 6 & \\\cline{3-6} & & & & 0& \\\end{array}[/tex]
[tex]\displaystyle 2)\; 4,25-3\frac{1}{20} =4,25-3,05=1,2[/tex]
[tex]\begin{array}{r} \underline{-\begin{array}{r}4,25 \\ 3,05\end{array}} \\ 1,20\hspace{0.5em}\end{array}[/tex]
[tex]\displaystyle 3)\;1,2+3,8=5[/tex]
[tex]\begin{array}{r} \underline{+\begin{array}{r}1,2 \\ 3,8\end{array}} \\ 5,0\hspace{0.5em}\end{array}[/tex]
[tex]\displaystyle 4)\;5:7=\frac{5}{7}[/tex]
[tex]\displaystyle 5)\; 1\frac{2}{7}+\frac{5}{7} =1\frac{2+5}{7}=1\frac{7}{7}=2[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
[tex]\displaystyle 1\frac{2}{7}+\left(4,25-3\frac{1}{20}+15,96:4\frac{1}{5}\right):7=2[/tex]
Пошаговое объяснение:
Найти значение выражения:
[tex]\displaystyle 1\frac{2}{7}+\left(4,25-3\frac{1}{20}+15,96:4\frac{1}{5}\right):7[/tex]
Расставим действия:
[tex]\displaystyle 1\frac{2}{7}\stackrel{(5)}+\left(4,25\stackrel{(2)}-3\frac{1}{20}\stackrel{(3)}+15,96\stackrel{(1)}:4\frac{1}{5}\right)\stackrel{(4)}:7[/tex]
[tex]\displaystyle 1)\;15,96:4\frac{1}{5}=15,96:4,2=159,6:42=3,8[/tex]
[tex]\arraycolsep=0.05em\begin{array}{c c c c r r @{\;}l | l}& 1 & 5 & 9, & 6 & & & \;42 \\\cline{1-1}\cline{8-8}~ & 1 & 2 & 6 & & & & \; 3,8\\\cline{2-5} & &3 & 3 & 6 & \\\cline{2-2} & & 3 & 3 & 6 & \\\cline{3-6} & & & & 0& \\\end{array}[/tex]
[tex]\displaystyle 2)\; 4,25-3\frac{1}{20} =4,25-3,05=1,2[/tex]
[tex]\begin{array}{r} \underline{-\begin{array}{r}4,25 \\ 3,05\end{array}} \\ 1,20\hspace{0.5em}\end{array}[/tex]
[tex]\displaystyle 3)\;1,2+3,8=5[/tex]
[tex]\begin{array}{r} \underline{+\begin{array}{r}1,2 \\ 3,8\end{array}} \\ 5,0\hspace{0.5em}\end{array}[/tex]
[tex]\displaystyle 4)\;5:7=\frac{5}{7}[/tex]
[tex]\displaystyle 5)\; 1\frac{2}{7}+\frac{5}{7} =1\frac{2+5}{7}=1\frac{7}{7}=2[/tex]