[tex]\displaystyle\bf\\Sin\Big(\frac{\pi }{2} -L\Big)-Cos\Big(\pi +L\Big)=CosL-(-CosL)=CosL+CosL=2CosL[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle\bf\\Sin\Big(\frac{\pi }{2} -L\Big)-Cos\Big(\pi +L\Big)=CosL-(-CosL)=CosL+CosL=2CosL[/tex]