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volchonok378910
@volchonok378910
July 2022
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за какое время автобус, трогаясь с места с ускорением 0,3 м/с^2, приобретает 54км/ч?
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obiniak
V=at
54 км/ч =3,6*15 м/с.
t=V/a=15/0.3=50 сек
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Answers & Comments
54 км/ч =3,6*15 м/с.
t=V/a=15/0.3=50 сек