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stepa555
@stepa555
July 2022
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13*(22+x)=15*(22-x)
Теплоход проходит за 15 ч. против течения реки столько же,сколько за 13 ч. по течению.Найдите скорость течения реки,если собственная скорость теплохода 22км/ч
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shushanna15
286+13х=330-15х13х+15х=330-28628х=44х=1,5км/ч
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