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sergei71d
@sergei71d
August 2022
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чему равно время падения тела с высоты 2400 м
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N1ckk
Verified answer
H=gt^2/2
gt^2= 2h
t^2 = 2h/g
t =√2h/g
t = √2*2400/10
t = √480 сек = 4√30 сек
Ответ: 4√30 сек.
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Answers & Comments
Verified answer
H=gt^2/2gt^2= 2h
t^2 = 2h/g
t =√2h/g
t = √2*2400/10
t = √480 сек = 4√30 сек
Ответ: 4√30 сек.