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Ответ:

дано

m(ppa KOH) = 1120 g

W(KOH) = 5%

V(SO3) = 4.48 L

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m(K2SO4)-?

m(KOH) = 1120*5% / 100% = 56 g

M(KOH) = 56 g/mol

n(KOH) = m/M = 56 / 56 = 1 mol

n(SO3) = V(SO3) / Vm = 4.48 / 22.4 = 0.2 mol

n(KOH) >n(SO3)

2KOH+SO3-->K2SO4+H2O

n(SO3) = n(K2SO4)

n(K2SO4) = 0.2  mol

M(K2SO4) = 174 g/mol

m(K2SO4) = n*M  = 0.2 * 174 = 34.8 g

ответ 34.8 г

Объяснение: