June 2021 0 6 Report
Через центр О квадрата ABCD проведен к его плоскости перпендикуляр KO. Угол между прямой КС и плоскостью квадрата равен 60градусам. AB=18 м. Вычислите угол между плоскостями: 1) AKC и DKB 2)ABC u BKC
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