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кирилл2911
@кирилл2911
July 2022
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через какие точки проходит график уравнения 3x+2y=6
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MizoriesKun
3х+2у=6 выразим переменную у через х
2у=6-3х
у=(6-3х) :2
х=0 у=(6-3*0):2=3 (0;3)
х=1 у=(6-3*1):2=3/2 (1;3/2)
х=2 у=(6-3*2):2=0 (2 ;0)
х=-2 у=(6-3*(-2)):2=6 (-2;6)
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Answers & Comments
2у=6-3х
у=(6-3х) :2
х=0 у=(6-3*0):2=3 (0;3)
х=1 у=(6-3*1):2=3/2 (1;3/2)
х=2 у=(6-3*2):2=0 (2 ;0)
х=-2 у=(6-3*(-2)):2=6 (-2;6)