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Chereshnyaaa66
@Chereshnyaaa66
November 2021
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Через проводник, обладающий сопротивлением 4 Ом, за 1.5мин прошла 36Кл электричества. Определите напряжение, приложенное к концам проводника.
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sokolovvovikn
Verified answer
Дано: R=4 Ом t=90 c Q=36 Кл U-?
U=I*R
I=Q/t
U=Q*R/t=36*4/90=1,6 A
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Verified answer
Дано: R=4 Ом t=90 c Q=36 Кл U-?U=I*R
I=Q/t
U=Q*R/t=36*4/90=1,6 A