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89641073871s
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July 2022
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Через раствор гидроксида натрия пропустили 4,48 л сернистого газа. Образовалось 126 г раствора сульфита натрия. Вычислите массовую долю соли в полученном растворе.
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janislav
Verified answer
N(SO2)=V(SO2)/Vм(SO2)=4,48/22,4=0,2 моль
SO2+2NaOH=Na2SO3+H2O
n(Na2SO3)=n(SO2)=0,2 моль
m(Na2SO3) = M(Na2SO3)*n(Na2SO3)=126*0,2= 25,2 г
ω(Na2SO3) = 25,2/126 * 100% = 20%
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Verified answer
N(SO2)=V(SO2)/Vм(SO2)=4,48/22,4=0,2 мольSO2+2NaOH=Na2SO3+H2O
n(Na2SO3)=n(SO2)=0,2 моль
m(Na2SO3) = M(Na2SO3)*n(Na2SO3)=126*0,2= 25,2 г
ω(Na2SO3) = 25,2/126 * 100% = 20%