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skmiloserden
@skmiloserden
May 2021
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определите кинетическую энергию тела массой 2 кг , движущегося со скоростью 72 км/ч
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fdd3
Ek=mv^2/2.72км/ч=20м/с.Ek=20^2*2/2=400Дж
1 votes
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skmiloserden
Cпасибо !
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