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нюша2605
@нюша2605
July 2022
2
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число √ 7 является нулем функции y=-3x^2+2bx-7, если b равно
1. √7
2. 14
3. 3√7
4. 7
5. 2√7
помогите пожалуйста
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Answers & Comments
svansen
Verified answer
0 = -3*7+2b√7-7
2b
√7 = 28
b = 14/
√7 = 2
√7
0 votes
Thanks 2
sedinalana
Verified answer
X=√7 ноль функции⇒у=0 при х=√7
-3*(√7)²+2b*(√7)-7=0
2√7 *b=7+21
2√7*b=28
b=28:2√7
b=14/√7
b=14√7/7
b=2√7
Ответ 5
1 votes
Thanks 1
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Answers & Comments
Verified answer
0 = -3*7+2b√7-72b√7 = 28
b = 14/√7 = 2√7
Verified answer
X=√7 ноль функции⇒у=0 при х=√7-3*(√7)²+2b*(√7)-7=0
2√7 *b=7+21
2√7*b=28
b=28:2√7
b=14/√7
b=14√7/7
b=2√7
Ответ 5