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polinavs2902
@polinavs2902
November 2021
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Число атомов водорода в 11,2л аммиака NH3
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Alexei78
Ответ смотри на фотографии.
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Кляксус
N (NH3) = V : Vm = 11,2 : 22,4 = 0,5 моль
n (H) = 3n (NH3) = 0,5 * 3 = 1,5 моль
N = n * Na = 1,5 * 6 * 10^23 = 9 * 10^23 атомов
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Answers & Comments
n (H) = 3n (NH3) = 0,5 * 3 = 1,5 моль
N = n * Na = 1,5 * 6 * 10^23 = 9 * 10^23 атомов