Home
О нас
Products
Services
Регистрация
Войти
Поиск
valeriaurash20
@valeriaurash20
August 2022
1
1
Report
cos ^2 x-12 cos x sin x=13sin^2 x п
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
treez0r
Cos²x-12cosxsinx-13sin²x=0 | :cos²x
1-12tgx-13tg²x=0
13tg²x+12tgx-1=0
(tgx+1)(13tgx-1)=0
tgx=-1
tgx=1/13
x1=-П/4+Пn, n€Z
x2=arctg(1/13)+Пk, k€Z
3 votes
Thanks 10
More Questions From This User
See All
valeriaurash20
August 2022 | 0 Ответы
2cos2 x4 1 1 pomogite pozhalujsta
Answer
valeriaurash20
August 2022 | 0 Ответы
tg4pi x 1 pomogite pozhalujsta ochen nuzhno
Answer
valeriaurash20
November 2021 | 0 Ответы
tg4pi x 1 pomogite ochen nuzhno
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "cos ^2 x-12 cos x sin x=13sin^2 x п..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1-12tgx-13tg²x=0
13tg²x+12tgx-1=0
(tgx+1)(13tgx-1)=0
tgx=-1
tgx=1/13
x1=-П/4+Пn, n€Z
x2=arctg(1/13)+Пk, k€Z