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TianDe1
@TianDe1
August 2022
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y’(x)=7sin(x+12)/cos(-5x)
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mikael2
Y=7sin(x+12)/cos(-5x) y'=(u/v)'=1/v²[u'v-v'u]
u=7sin(x+12) u'=7cos(x+12)
v=cos(-5x)=cos5x v'=-5sin5x
y'=1/cos²5x[7cos(x+12)*cos5x+5sin5x*7sin(x+12)]=
=7[cos(x+12)*cos5x+5sin5x*sin(x+12)]/cos²5x
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Answers & Comments
u=7sin(x+12) u'=7cos(x+12)
v=cos(-5x)=cos5x v'=-5sin5x
y'=1/cos²5x[7cos(x+12)*cos5x+5sin5x*7sin(x+12)]=
=7[cos(x+12)*cos5x+5sin5x*sin(x+12)]/cos²5x