100 баллов Упростить Ctg a(((1+sin^2 a)/cos a ) - cos a). Created by Dgoker2. algebra-ru

cos a ) - cos a)...

Dgoker2 @Dgoker2

July 2022 1 14 Report

100 баллов
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Ctg a(((1+sin^2 a)/cos a ) - cos a)

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red321

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$ctga((\frac{1+sin^2a}{cosa})-cosa)=\frac{cosa}{sina}((\frac{cos^2a+sin^2a+sin^2a}{cosa})-cosa)=\\=\frac{cosa}{sina}(cosa+\frac{2sin^2a}{cosa}-cosa)=\frac{cosa}{sina}*\frac{2sin^2a}{cosa}=2sina$

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