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dvbjfs
@dvbjfs
July 2022
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(sin 2 a/sin a)-(cos2a/cos a)
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ATLAS
Verified answer
(sin2a/sina)-(cos2a/cosa)=(sin2a*cosa-cos2a*sina)/(sina*cosa)=
=sin(2a-a)/(sina*cosa)=sina/(sina*cosa)=1/cosa
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Answers & Comments
Verified answer
(sin2a/sina)-(cos2a/cosa)=(sin2a*cosa-cos2a*sina)/(sina*cosa)==sin(2a-a)/(sina*cosa)=sina/(sina*cosa)=1/cosa