a)=(sin2α-sinα) /(cosα-1/2)=(2sinαcosα-sinα) /(cosα-1/2)=2sinα(cosα-1/2) /(c0sα-0,5)=2sinα.
б)=(sin3α-sinα) /(cosα-cos3α)=2sinαcos2α /2sinαsin2α=cos2α/sin2α=ctg2α.
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
a)=(sin2α-sinα) /(cosα-1/2)=(2sinαcosα-sinα) /(cosα-1/2)=2sinα(cosα-1/2) /(c0sα-0,5)=2sinα.
б)=(sin3α-sinα) /(cosα-cos3α)=2sinαcos2α /2sinαsin2α=cos2α/sin2α=ctg2α.