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asylsezim
@asylsezim
August 2022
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cos фи=1 фи принадлежит [-пи;5пи]
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KuOV
Verified answer
Будем использовать вместо фи х.
cosx = 1 x∈[- π ; 5π]
x = 2πn, n∈Z
- π ≤ 2πn ≤ 5π
- 1 ≤ 2n ≤ 5
-1/2 ≤ n ≤ 2,5
Так как n ∈ Z,
n = 0: x = 0
n = 1: x = 2π
n = 2: x = 4π
Указанному отрезку принадлежат корни уравнения: 0; 2π; 4π.
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Answers & Comments
Verified answer
Будем использовать вместо фи х.cosx = 1 x∈[- π ; 5π]
x = 2πn, n∈Z
- π ≤ 2πn ≤ 5π
- 1 ≤ 2n ≤ 5
-1/2 ≤ n ≤ 2,5
Так как n ∈ Z,
n = 0: x = 0
n = 1: x = 2π
n = 2: x = 4π
Указанному отрезку принадлежат корни уравнения: 0; 2π; 4π.