3√2(cos35-sin35)/cos100. Created by sysloslon. matematika-ru

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October 2021 1 16 Report

3√2(cos35-sin35)/cos100

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3√2(cos35-sin35)/cos100=
=3√2(sin(45-10)-sin(45+10))/cos(90+10)=
=3√2(sin(45)*cos(10)-sin(10)*cos(45)-sin(45)*cos(10)-sin(10)*cos(45))/sin(10)=
=3√2(-2*sin(10)*cos(45))/sin(10)=
=3√2(-2*cos(45))=3√2(-2*√2/2)=-6

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