cos(1,5pi + 2x) = cos x
решить уравнение
sin2x-cosx=0
2sinxcosx-cosx=0
cosx(2sinx-1)=0
cosx=0 sinx=1/2
x=pi/2+pi n x=(-1)^k*pi/6+pi k
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Answers & Comments
cos(1,5pi + 2x) = cos x
sin2x-cosx=0
2sinxcosx-cosx=0
cosx(2sinx-1)=0
cosx=0 sinx=1/2
x=pi/2+pi n x=(-1)^k*pi/6+pi k