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mimi08
@mimi08
July 2022
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cos^2 x - sin^2 x = 0 , 5
решите пожалуйста
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yuliaayu
1-sin^2x-sin^2x=1/2
-2sin^2x=-1/2
sin^2x=1/4
sinx=+-1/2
x1=pi/6 +pi*k где k принадлежит z
x2= -pi/6 + pi*k где k принадлежит z
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Answers & Comments
-2sin^2x=-1/2
sin^2x=1/4
sinx=+-1/2
x1=pi/6 +pi*k где k принадлежит z
x2= -pi/6 + pi*k где k принадлежит z