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montpellier
@montpellier
July 2022
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(1/tg x)*(1/cos^2 x)
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Юленька194
Verified answer
(1/tg x)*(1/cos² x)= (1/tg x)*(tg²x +1)=(tg²x +1)/tgx = tg²x/tgx +1/tgx = tgx+ctgx
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Verified answer
(1/tg x)*(1/cos² x)= (1/tg x)*(tg²x +1)=(tg²x +1)/tgx = tg²x/tgx +1/tgx = tgx+ctgx