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Биконя
@Биконя
June 2021
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1/cos^2a-tg^2a-sin^2a
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lstava
Verified answer
1/cos²α - tg²α - sin²α = 1/cos²α - sin²α/cos²α - sin²α = (1 - sin²α)/cos²α - sin²α = cos²α/cos²α - sin²α = 1 - sin²α = cos²α
Использовались соотношения
tgα = sinα/cosα, sin²α + cos²α = 1
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Verified answer
1/cos²α - tg²α - sin²α = 1/cos²α - sin²α/cos²α - sin²α = (1 - sin²α)/cos²α - sin²α = cos²α/cos²α - sin²α = 1 - sin²α = cos²αИспользовались соотношения
tgα = sinα/cosα, sin²α + cos²α = 1