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199911071
@199911071
August 2022
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cos2x =sin (П+ x) решите плизз
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oganesbagoyan
Verified answer
Cos2x =sin(π+x) ;
1 -2sin²x = -sinx ;
2sin²x -sinx -1 =0 ; * * * t = sinx , -1 ≤ t ≤ 1 * * *
[ sinx = -1/2 ; sinx =1 .
[ x =(-1)^(n+1)π/6+πn ; x=π/2+2πn , n∈Z.
ответ :
(-1)^(n+1)π/6+πn ; π/2+2πn , n∈Z.
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Verified answer
Cos2x =sin(π+x) ;1 -2sin²x = -sinx ;
2sin²x -sinx -1 =0 ; * * * t = sinx , -1 ≤ t ≤ 1 * * *
[ sinx = -1/2 ; sinx =1 .
[ x =(-1)^(n+1)π/6+πn ; x=π/2+2πn , n∈Z.
ответ : (-1)^(n+1)π/6+πn ; π/2+2πn , n∈Z.