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pindaks
@pindaks
July 2022
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Cos^2x-sinxcosx=0
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шекастаяя
Cos ^ 2x - sinx cosx - sin ^ 2 (x) - cos ^ 2 (x) = 0
sin ^ 2 + sin * cos = 0
sin * (1 + cos) = 0
sin (x) = 0
x = 0, pi
------
1 + cos = 0
cos (x) = -1
x = pi
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Answers & Comments
sin ^ 2 + sin * cos = 0
sin * (1 + cos) = 0
sin (x) = 0
x = 0, pi
------
1 + cos = 0
cos (x) = -1
x = pi