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pavanna2010
@pavanna2010
July 2022
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cos2x+3sinx-2=0
sin2x-6sinx=0
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shevtsovavalia
1)cos2x+3sinx-2=0
1-2sin²x+3sinx-2=0
sinx=a
2a²-3a+1=0
D=1
a=1; sinx=1 ⇒x=π/2+2πn
a=1/2; sinx=1/2⇒x=(-1)ⁿπ/6+πn
2)sin2x-6sinx=0
2sinx*cosx-6sinx=0
2sinx(cosx-3)=0
sinx=0
x=πn
1 votes
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Answers & Comments
1-2sin²x+3sinx-2=0
sinx=a
2a²-3a+1=0
D=1
a=1; sinx=1 ⇒x=π/2+2πn
a=1/2; sinx=1/2⇒x=(-1)ⁿπ/6+πn
2)sin2x-6sinx=0
2sinx*cosx-6sinx=0
2sinx(cosx-3)=0
sinx=0
x=πn