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RE4R
@RE4R
August 2022
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cos2x=5sinx+3 помогите пожалуйста
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mikael2
Verified answer
Сos2x=1-2sin²x
1-2sin²x-5sinx-3=0 -2sin²x-5sinx-2=0
2sin²x+5sinx+2=0 √D=√(25-16)=√9=3
sinx=1/4[-5-3]=-2 но sinx≤1
sinx=1/4[-5+3]=-1/2 x=(-1)ⁿ(-π/6)+πk k∈Z
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Answers & Comments
Verified answer
Сos2x=1-2sin²x1-2sin²x-5sinx-3=0 -2sin²x-5sinx-2=0
2sin²x+5sinx+2=0 √D=√(25-16)=√9=3
sinx=1/4[-5-3]=-2 но sinx≤1
sinx=1/4[-5+3]=-1/2 x=(-1)ⁿ(-π/6)+πk k∈Z