Спростити вираз (sin^[2]x-sin2x+3cos^[2]x)/cos^[2]x. Created by Стрілець4000. algebra-ru

cos^[2]x...

September 2021 1 4 Report

Спростити вираз (sin^[2]x-sin2x+3cos^[2]x)/cos^[2]x

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mishka19 $\frac{sin^2x-sin2x+3cos^2x}{cos^2x}= \frac{sin^2x-2sinxcosx+3cos^2x}{cos^2x}= \\ \\ =\frac{sin^2x}{cos^2x}-\frac{2sinxcosx}{cos^2x}+\frac{3cos^2x}{cos^2x}=tg^2x- \frac{2sinx}{cosx} +3= \\ \\ =tg^2x-2tgx+3$

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