cos 6a /(cos3a -sin3a). Created by shchipakinas. algebra-ru

(cos3a -sin3a)...

Lesben

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Cos6a/(cos3a-sin3a)=cos(2.3a)/(cos3a-sin3a)=
=(cos²3a-sin²3a)/(cos3a-sin3a)=(cos3a+sin3a)(cos3a-sin3a)/(cos3a-sin3a)=
=cos3a+sin3a

(cos2x=cos²x-sin²x)
(cos²x-sin²x=(cosx+sinx)(cosx-sinx))

1 votes Thanks 2

Lesben ......./(cos3a-sin3a)=cos3a+sin3a

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MizoriesKun

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Cos 6a /(cos3a -sin3a)=Cos 2 (3a) /(cos3a -sin3a) =

=(cos²3a -sin²3a/(cos3a -sin3a) =

=(cos3a -sin3a)*(cos3a +sin3a) /(cos3a -sin3a)=

= cos3a + sin3a

4 votes Thanks 5

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