cos3x=0 найти min max [0:П]
cos3x=0
3х=П/2+Пn
х=П/6+Пn/3
min х=П/6+П*0/3= х=П/6
max х=П/6+П*П/3=(2П+(П^2))/6
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cos3x=0
3х=П/2+Пn
х=П/6+Пn/3
min х=П/6+П*0/3= х=П/6
max х=П/6+П*П/3=(2П+(П^2))/6