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kozhukhovamash
@kozhukhovamash
July 2022
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СРОЧНО!!!
Для острых углов α и β докажите тождество (1+tg^2 α)^2-1/(cos^4 α)+3cos^2 β+2sin^2 β=2+cos^2 β
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m11m
Verified answer
(1+tg²α)² - 1/(cos⁴α) + 3cos²β + 2sin²β=
= (1/cos²α)² - 1/cos⁴α + 3cos²β + 2(1-cos²β)=
= 1/cos⁴α - 1/cos⁴α + 3cos²β + 2 - 2cos²β =
=2 + cos²β
2+cos²β = 2 + cos²β
Что и требовалось доказать.
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kozhukhovamash
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Answers & Comments
Verified answer
(1+tg²α)² - 1/(cos⁴α) + 3cos²β + 2sin²β== (1/cos²α)² - 1/cos⁴α + 3cos²β + 2(1-cos²β)=
= 1/cos⁴α - 1/cos⁴α + 3cos²β + 2 - 2cos²β =
=2 + cos²β
2+cos²β = 2 + cos²β
Что и требовалось доказать.