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Илья228nsk
@Илья228nsk
August 2022
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cos^4X + sin^3X=1
Помогите пожалуйста!!
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AnonimusPro
Verified answer
(1-sin^2x)^2+sin^3x=1;
1-2*sin^2x+(sin^2x)^2+sin^3x=1;
sin^4x+sin^3x-2*sin^2x=0;
sin^2x(sin^2x+sinx-2)=0;
sin^2x=0;
x1=0;
sin^2x+sinx-2=0;
sinx=u;
u^2+u-2=0;
D=9; u1=1; u2=-2;
sinx=1; x2=pi/2;
sinx=-2, x - не подх по одз
Ответ: x1=0; x2=pi/2
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Answers & Comments
Verified answer
(1-sin^2x)^2+sin^3x=1;1-2*sin^2x+(sin^2x)^2+sin^3x=1;
sin^4x+sin^3x-2*sin^2x=0;
sin^2x(sin^2x+sinx-2)=0;
sin^2x=0;
x1=0;
sin^2x+sinx-2=0;
sinx=u;
u^2+u-2=0;
D=9; u1=1; u2=-2;
sinx=1; x2=pi/2;
sinx=-2, x - не подх по одз
Ответ: x1=0; x2=pi/2