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aahiev
@aahiev
August 2021
2
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Cos²α-(ctg²α+1)sin²α
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Droko
2 votes
Thanks 2
melanika58
а куда ты дел ctg²α+1?
melanika58
Сos^2-(ctg²α+1)sin^2a
Сos^2-(c*sin^2a*t*sin^2a*g^2*sin^2a*a*sin^2a+sin^2a)
Приводим подобные,
Сos^2-(сtg²α(sin^2a)^4+sin^2a)
Но я не уверена
0 votes
Thanks 0
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Answers & Comments
Сos^2-(c*sin^2a*t*sin^2a*g^2*sin^2a*a*sin^2a+sin^2a)
Приводим подобные,
Сos^2-(сtg²α(sin^2a)^4+sin^2a)
Но я не уверена