Home
О нас
Products
Services
Регистрация
Войти
Поиск
romikkjh
@romikkjh
August 2022
1
5
Report
cosA+sinA=1
A-?
решите 3 способами
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
CosA+cos(π/2-A)=1
2cosπ/4cos(A-π/4)=1
2*√2/2cos(A-π/4)=1
cos(A-π/4)=1/√2
A-π/4=-π/4+2πk U A-π/4=π/4+2πk
A=2πk U A=π/2+2πk,k∈z
1-2sin²A/2+2sinA/2*cosA/2=1
2sinA/2*(cosA/2-sinA/2)=0
sinA/2=0⇒a/2=πk⇒a=2πk
cosA/2-sinA/2=0/cosA/2
1-tgA/2=0⇒tgA/2=1⇒A/2=π/4+πk⇒A=π/2+2πk,k∈z
sin(π/2-A)+sinA=1
2sinπ/4*cos(x-π/4)=1
2*√2/2cos(A-π/4)=1
cos(A-π/4)=1/√2
A-π/4=-π/4+2πk U A-π/4=π/4+2πk
A=2πk U A=π/2+2πk,k∈z
1 votes
Thanks 1
romikkjh
cosA+cos(π/2-A)=1
romikkjh
а откуда взялось (π/2-A)
More Questions From This User
See All
romikkjh
August 2022 | 0 Ответы
kak poluchit iz gidroksida natriya digidroortofosfat natriya
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "cosA+sinA=1 A-? решите 3 способами..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2cosπ/4cos(A-π/4)=1
2*√2/2cos(A-π/4)=1
cos(A-π/4)=1/√2
A-π/4=-π/4+2πk U A-π/4=π/4+2πk
A=2πk U A=π/2+2πk,k∈z
1-2sin²A/2+2sinA/2*cosA/2=1
2sinA/2*(cosA/2-sinA/2)=0
sinA/2=0⇒a/2=πk⇒a=2πk
cosA/2-sinA/2=0/cosA/2
1-tgA/2=0⇒tgA/2=1⇒A/2=π/4+πk⇒A=π/2+2πk,k∈z
sin(π/2-A)+sinA=1
2sinπ/4*cos(x-π/4)=1
2*√2/2cos(A-π/4)=1
cos(A-π/4)=1/√2
A-π/4=-π/4+2πk U A-π/4=π/4+2πk
A=2πk U A=π/2+2πk,k∈z