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NasarogDen
@NasarogDen
July 2022
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cos(L+B)+sin l sinB =cosl
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nazarzakap
CosL*cosB-sinL*sinB+sinl*sinB=cosl
Cosl*cosB=cosl
1 votes
Thanks 1
Hekardo
Cos(l+b)+sinl sin b=cos l
cos l * cos b-sin l * sin b+sin l - sin b=cos l
cos l * cos b=cos l
cos l(cos b - 1)=0
cos l =0 cos b = 1
l=π/2+πn, n∈Z b=2πn, n∈Z
0 votes
Thanks 2
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Answers & Comments
Cosl*cosB=cosl
cos l * cos b-sin l * sin b+sin l - sin b=cos l
cos l * cos b=cos l
cos l(cos b - 1)=0
cos l =0 cos b = 1
l=π/2+πn, n∈Z b=2πn, n∈Z