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ХимБио2
@ХимБио2
August 2021
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(cos3x/sinx)+(sin3x/cosx)
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sedinalana
Verified answer
(cos3x)/(sinx)+sin3x)/(cosx)=(cos3x*cosx+sin3x*sinx)/(sinx*cosx)=
=cos(3x-x)/(0,5sin2x)=(2cos2x/(sin2x)=2ctg2x
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Verified answer
(cos3x)/(sinx)+sin3x)/(cosx)=(cos3x*cosx+sin3x*sinx)/(sinx*cosx)==cos(3x-x)/(0,5sin2x)=(2cos2x/(sin2x)=2ctg2x