Ответ:
2Cr + 6H2SO4 → Cr2(SO4)3 + 6H2O + 3SO2
2Cr⁰ + 6 H⁺₂S⁻⁶O⁻²₄ → Cr³⁺₂(S⁻⁶O⁻²₄)₃ + 3S⁴⁺O²⁻₂ + 6 H⁺₂O²⁻
3 S⁻⁶ + 6 e- → 3 S⁺⁴
Cr⁰ - 6 e- → 2 Cr³⁺
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Ответ:
2Cr + 6H2SO4 → Cr2(SO4)3 + 6H2O + 3SO2
Verified answer
2Cr⁰ + 6 H⁺₂S⁻⁶O⁻²₄ → Cr³⁺₂(S⁻⁶O⁻²₄)₃ + 3S⁴⁺O²⁻₂ + 6 H⁺₂O²⁻
3 S⁻⁶ + 6 e- → 3 S⁺⁴
Cr⁰ - 6 e- → 2 Cr³⁺