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girlssmechinka
@girlssmechinka
July 2022
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помогите упростить выражения
1)sin^2a+cos^2a+tg^2b
2)tga/ctga(1-sin^2a)
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1nastyazimina1
1)sin^2a+cos^2a+tg^2b=1+tg^2b=1/cos^2b
2)по основному правилу cos^2t+sin^2t=1, cos^2t=1-sin^2t
tga/ctga(1-sin^2a)=sina/cost*sina/cosa*cosa=sin^2a/cosa
2 votes
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Answers & Comments
2)по основному правилу cos^2t+sin^2t=1, cos^2t=1-sin^2t
tga/ctga(1-sin^2a)=sina/cost*sina/cosa*cosa=sin^2a/cosa