Ответ:
Объяснение:
МCu(NO3)2 = 64 + (14 + 16 * 3) * 2 = 188 г/моль
w(Cu) = Ar(Cu)* n/МCu(NO3)2 * 100% = 64/188 * 100% = 34%
w(N) = Ar(N)* n/МCu(NO3)2 * 100% = 14 * 2/188 * 100% = 14,9%
w(O) = Ar(O)* n/МCu(NO3)2 * 100% = 16 * 6/188 * 100% = 51,1%
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Ответ:
Объяснение:
МCu(NO3)2 = 64 + (14 + 16 * 3) * 2 = 188 г/моль
w(Cu) = Ar(Cu)* n/МCu(NO3)2 * 100% = 64/188 * 100% = 34%
w(N) = Ar(N)* n/МCu(NO3)2 * 100% = 14 * 2/188 * 100% = 14,9%
w(O) = Ar(O)* n/МCu(NO3)2 * 100% = 16 * 6/188 * 100% = 51,1%