m(Cu(OH)2) = 64 + (16 *2) + (1*2) = 98 г/моль
W(Cu) = 64/98 = 65.3%
W(O) = 32/98 = 32.6%
W(H) = 2/98 = 2%
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m(Cu(OH)2) = 64 + (16 *2) + (1*2) = 98 г/моль
W(Cu) = 64/98 = 65.3%
W(O) = 32/98 = 32.6%
W(H) = 2/98 = 2%