Verified answer

Ответ: ≈1,767.

Объяснение:

[tex]\displaystyle\\\frac{3-\sqrt{3} }{\sqrt{6} -\sqrt{3} } =\frac{(3-\sqrt{3})*(\sqrt{6}+\sqrt{3}) }{(\sqrt{6} -\sqrt{3})*(\sqrt{6}+\sqrt{3}) } =\frac{3\sqrt{6}+3\sqrt{3} -\sqrt{3}*\sqrt{6} -\sqrt{3}*\sqrt{3} }{(\sqrt{6})^2-(\sqrt{3})^2 } =\\\\\\=\frac{3\sqrt{6}+3\sqrt{3}-\sqrt{3*3*2} -3 }{6-3} =\frac{3\sqrt{6}+3\sqrt{3} -3\sqrt{2} -3 }{3} =\\\\\\=\frac{3*(\sqrt{6}+\sqrt{3}-\sqrt{2} -1) }{3} =\sqrt{6}+\sqrt{3}-\sqrt{2} -1\approx1,767.[/tex]